Sudoku Puzzles

Perhaps, but I hope they have better things to talk about!

Christmas dinner.

Shiela, i agree with you. Have a good day /night all of us!!! /

a haggle in a gaggle?

Nice to see you all again!!!

That's a great comment, appy!

Gossiping geese.

26:42 Maen! Maybe the geese will come up with a good solution for it...

It is a very relaxing picture! Thanks!

The contrasts and the reflections are lovely Appy!!

25:19

Always a possibility appy.

A long path for this one:

1)Start at 22,basic techniques to UP=31
2)(578=6)cgh2-i12=i7-(6=7)d7,=>d2<>7.UP=33
3)(9)a3=(9-8)c1=(8-2)g1=(2)h3,=>h3< ;>9
4)(2=3)e7-i7=(3-4)i6=c6-(4=9)a4-(9=5)a3-(5=2)h3,=>h7<>2.UP=34
5)(5=3)h7-i7=(3-4)i6 More...

Hi sotir,
After UP31, look at AUR(27)bc48 => (4)c8=(49)c4 and consider bivalue cell (49)a4:
AUR(27)bc48:(4)c8=(49)ac4 => c6<>4, UP40 then one more XY-wing to UP81

ttt

Hi ttt,
Excellent finding.Thanks for sharing with us.I also saw AUR(27)bc48:=>(4)c8=(7)c5,=>a8<>7.This didn't help me for a shorter solution,so I try another path.I should be continue:
(4)c8=(7)c5-(3)c5=(3)c6,=>c8<>7,c6<>4
Best Regards,Sotir.

43:36

also the well known AUR deduduction where one of the numbers in the ceiling (naked pair) is strong with one of the floor corners exludes the other number in the other floor corner:

(ab)==(ab)
||
(a..b*)--(ab) <--~b

unfortunately if you make that deduction ttt's deduction disappears from view!

SE=7.4

1.UP=31 (note AUR(27)bc48:(2)c9=(7)c5)
2.(3)c6=(3-7)c5=(2)c9-(27=4)bc8 => c6<>4,c8<>7, UP=41
3.(9=8)c1-(8=29)h3g1 => i1<>9, UP=81.

1.SST to UP31
2.aur(27)bc48:(4)c8=(7-3)c5=c6 > -7c8 -4c6 UP42
3.YW(692)if1h3 > -2g1f3 UP81