Sudoku Puzzles

Hi to all. Still quiet here...

1. Unique possibilities:a4=7,c1=3,g9=4,h4=8 (UP 26).
2. If b4=9,i6=9,i7=3,h8=7 and right middle box is devoid of 7.So b4=6,g4=9 (UP 28).
3. When i3=3,pair 28 at eg3,d3=4,i7=9,d6=6 and column e is devoid of 6,due to pair 79 at e19.Hence g3=3 (UP 29).
4. If More...

Noticed later,there is no need for my step 3.

Oh! Wagdy!
I think I like this one the best so far! Nice!

long time >2 hrs

Ah, Alfred, I used your step 3, not for solving for the 3, but for noticing I missed the 12 pair in e, which results in the 79 pair you used, that I was missing. Once I noticed all the pairs in e, the rest was not hard.

17:44 Anyone know what kind of tree is in the middle -- the one that looks like green poodle tails?

24:05
Didn't take me long at all.
Maybe I made an error?

SE=8.4

1)Start at 22,SSTS to UP=26
2)(7)i6=h6-(7=3)h8-(3=9)i7,=>i6<>9.UP=28
3)Loop:(4=6)d6-(6=58)e56-(8=2)e3-(2=4)d3,= >e1<>8,gi3<>2,d2<>4
4)(hp68=7)gi1-(7=1298)e1743,=>gi3<>8.UP=65
5)YW: (7=6)i6-(6=2)g5-(2=7)g2,=>i2<>7.UP=81

sotir - only reach UP33 after your step 4, did you forget to add a step?

possible conclusion:
4...UP33
5.(4=8)a3-e3=(89')cf2 > -4c2, UP65
6.YW(672)i26g5 > -2g2i5, UP81.