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Submitted by: Gath

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Cute little bison! Olahoma??? Is that near Oklahoma?
20/Aug/08 12:07 AM
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, Shiela. That reminds me: I had a student once named Lahoma. I was tempted, several times, when she asked a question, to say "OK, Lahoma."
20/Aug/08 12:51 AM
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Very nice Sue. Glad to be back
20/Aug/08 1:06 AM
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This the same park that had that beautiful statue of the pioneer woman and her son. Hal, I can see why it was so tempting to say "OK" to your student. Good thing you were not studying oak trees!!
20/Aug/08 1:22 AM
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11:42 My grandmother-in-law was named Lahoma, but I don't think she was HalT's student. To my knowledge she never went to school in S. Carolina. Plus, that would make HalT very, very old. Another nice bronze.
20/Aug/08 6:17 AM
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All this Tom-foolery from a misspelled word...love the trains (no Plunnel talk, Please!)of thought, what they prompt in others and where we go from there!
Great picture, btw, Sue!
20/Aug/08 7:32 AM
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Wonderful - puzzle, photo & banter!! Thanks everyone!
20/Aug/08 8:43 AM
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19:25
20/Aug/08 11:04 AM
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UP at f7, f8, pairs 48 at e46, 15 at h9,i7 and 36 at e19.
If 6 is in i5 or i6, then g1=6, e1=3, e9=6.
If e1=3, triple 127 at f123, and so f4=9, f5=3.
With e1=3, f5=3, e9 should be 3 which is not possible. So 6 cannot be at i5 or i6.
Thus i2=6.
UP 81.
20/Aug/08 3:00 PM
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A long path:
1)Start at 23,=>UP=25
2)(5):a2=a7-i7=i2,=>b2,c27<>5
3)(1):a9=h9-h4=f4-f1=a1,=>h6f3<>1
4 )(6):c4=c9-e9=e1-g1=g4,=>a4d9<>6
5)fc:(237)f123=(1)f1-(1)f4=(1)h4-(1)h9=(1-5)i7=(5-6)i2=(6 -8)d2=(8)d3
=>d23<>23 (two effective More...
21/Aug/08 12:00 AM
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Sorry. There are serious basic logic errors in my earlier 'proof'. Please treat that proof as withdrawn. I apologise.
21/Aug/08 2:35 AM
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45:57
23/Aug/08 2:51 AM
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