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Submitted by: kevin

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just about to start
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thought I'd skip to the tough first - just to see if I could be first - but alas
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3:54
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Forgot to set the timer doh!
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I am not first but I am here.
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c'mon Brick from Brizzy, whom are you kidding?
it took me longer to put all the possibilities in
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to george from romania
george you're just envious;)
Brick does it without setting up (read yday)
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15:00 why same bird?or is it diff.
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even i do it w/o any settingup.i tried with the red blinkers.then too i took a solid seven mts. to complete the grid.kudos to brick if he is so fast
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I'm having trouble posting this comment. There's an interesting article about the mathematics of sudoku. URL is
http://www.americanscientist.org/template/AssetDetail/assetid/48550?&print=yes

In discussing the distinction between trial-and-error and logic, says: 'Backtracking itself can be viewed as a logical operation; it supplies a proof by contradiction. '
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19:23
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Here's my full solution. Usual disclaimer about typos -- I'm sure that it's not the simplest, but it got the job done.

Part 1:

1. In column-i, 1 must be in i8 or i9; eliminate from i4, i5 & i6
2. In column-f, 1 must be in f2 or f3; eliminate from f4 & f5
3. In column-g, 2 must be in g8 or g9; eliminate from g4 & g6
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Part 2:

4. a1 & a2 must = 2 or 8; elimiante from rest of column-a
5. Easy elimination: e8=3, c7=3, g3=3
6. e9 & f9 must = 6 or 7; eliminate from rest of row-9
7. In column-d; 8 must be in d7 or d8; eliminate from d5 & d6
8. In row-3, 9 must be in a3 or b3; eliminate from c1 & c2
9. In column-d, 5, 8 & 9 must be in d7, d8 or d9; eliminate from rest of column
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Part 3:

10. In column-f, 1, 5 & 6 must be in f1, f2 or f3; eliminate from rest of column & 3x3
11. East elimination: f9=7, e9=6
12. In row-8, 6 must be in a8 or c8; eliminate from g8 & i8
13. Easy elimination: g6=6 (6 eliminated from all other cells in column), a5=6, c8=6, c4=9, More...
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Part 4:

14. In column-c, 7 must be in c1 or c2; eliminate from c6
15. b5 & b6 must = 5 or 8; eliminate 1, 4 & 7 from these cells
16. Easy elimination: b4=7 (7 eliminated from all other cells in 3x3), e6=7, e5=5, b5=8, b6=5
17. Looking at e2 = 2 or 4, can conclude that i4=3; proof: More...
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Hey Howard........Those American scientists are justs cheats who are too big-headed to admit it !
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Part 5:

18. Easy elimination: a6=3
19. Looking at d5 = 1 or 4, can conclude that i6=8; proof if d5=1, then h5=4 & i6=8; if d5=4, then e4=2, h6=2 & i6=8
20. h1 & h2 must = 5 or 8; eliminate 4, 6 & 7 from these cells
21. Easy elimination: h7=7, i7=6, h3=6, f3=1, b3=4, c1=7, i1=4, d1=2, ... easy eliminations to end
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Howard & Rob... having read the article, I don't think that this person is making that statement absolutely. Rather, he is saying that the argument can be made that it's a type of logic -- albeit not that type most refer to when we say solving the puzzle by logic alone.

He does go so far as to say that deduction such a what I used in step 19 is not 'trial and error.'
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Actually, he doesn't say that outright... he just says, 'David Eppstein of the University of California at Irvine has formulated some extremely subtle Sudoku rules, which capture the kind of information gleaned from a backtracking analysis, yet work in a forward-looking, nonspeculative mode.'
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All that work to get the same dumb bird???

We need better pictures on tough!
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cool bird 4:45 with an astonishingly large amount of help
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and scientist and proud
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1:22! I think the timer must be wrong cos that's no way I finished it in 1:22...
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The article and some of the mild controversey in these comment pages has to do with terminology. The article says: 'If you solve by logic, you never write a number into a cell until you can prove that only that number can appear in that position.' And by that definition, your step 19 is logical -- i6 can only be 8.
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But then the article says: 'For the logic-only strategy to work, a puzzle must have a quality of progressivism: At every stage in the solution, there must be at least one cell whose value can be determined unambiguously. ... The backtracking protocol dispenses with progressivism: When you reach a More...
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In my opinion, TMs derivation is entirely logical. No cell is filled in until the value has been proven correct. But one does reach a point where every vacant cell has at least two candidates. And alternatives have to be explored; the choices of which alternatives to explore is arbitrary.
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About the step 19: it is still logical since one has to find a chain within the grid and not only within a single column, row or block. It's not a random choise, neither a 'trial'. When you find that chain, whether you read it one way, you get a number, whether you read it in the other way, you still get the same number (I mean clockwise or anticlockwise since we are talking about oddgons)
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I did it, without mistakes or checking moves, but it took me a long time(37 minutes). Used several hidden triples and 2 forcing chains. A ton of work to get the same pic. LOL. Does anyone have any tips on selecting the cells to try for the forcing chains?
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Sorry Mike, no tips on selecting the cells. That's the only 'trial and error' I use when solving. If I'm lucky, I pick a cell that works on the first try. Sometimes, I need to test 4-5 different cells before I find one that works.
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4:46 My time was a bit faster than the Hard level :)
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I think that is a beautiful picture of the bird and feeder.
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12;04 Great time for me. Picture is a treat since the hummingbirds have gone south and will not be seeing them again until spring...May in the states.
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Having a problem with step #15, why must 'b5 & b6 must = 5 or 8;' I have 8 for a possibility in b4, where did I miss that elimination, or what is the thought process for b5 & b6 being 5 or 8?
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i did the easy then skiped 2 the tough, didn't take me long
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Nevermind, after posting my comment/question I noticed my puzzle was erased, so decided to go back through solving it your way. Thanks! For all the work
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Hi everyone! to easy I go. did ok today time? don't time myself.
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