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submitting questions

Submitted by: kevin

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Where's Keith???
31/May/09 12:07 AM
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There must be a story behind this one!
31/May/09 12:16 AM
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Shiela, are you saying that you think Keith would pose as a woman ... or as a big, ugly fish?
31/May/09 12:23 AM
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Have a nice Sunday all of us!!!!!
31/May/09 12:53 AM
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Or maybe just splashing about, clothed I hope?
31/May/09 1:00 AM
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1. Note pairs:23 at e8/f9;56 at d1/e2;47 at b3/c2.Unique possibilities to 29.
2. Note pairs;67 at g46;35 at eh4.If e8=2,a5=2,e3=9,a3=1=h1,a8=9=c1,c6=1,e4=3,h4=5.This would create a 15 rectangle at bi89,which could not be resolved.Hence e8=3 and UPs to 81.
31/May/09 1:41 AM
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12:00
31/May/09 4:53 AM
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Not sure I'd want to be mounted on a prow, especially in that silly hat.
31/May/09 7:01 AM
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Captain Arthur looks pretty funny mounted on that prow, in a silly hat. If he can do it, you can, too, Keith. i don't know if you'd want to wear that dress, though.
31/May/09 7:53 AM
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39:15
31/May/09 7:55 AM
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16:45, I'm trying to place just where that is in Sydny but I'm not sure. Maybe somewhere near the entrance to Government House.
31/May/09 9:42 AM
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1} Start at 23,basic techniques to UP=33
2) (16)bc9=(1)h9-(1=2)h1-(2)f1=(2)f9,=>c9<>2.UP=81
31/May/09 4:00 PM
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There is some lore (that escapes me at the moment) surrounding why ships always had women on the front. Nice pic
31/May/09 10:50 PM
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the logic in sotir's step 2 is invalid.
(16)bc9 and (1)h9 can both be false when i9=1.
the correct chain to prove c9<>2 is:
(2=3)f9-(3=9)f5-(9=67)b54-(6)b9=(6)c9.
15/May/10 11:49 PM
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SE=7.2
09/Sep/10 10:41 PM
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