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Submitted by: Gath

Indicate which comments you would like to be able to see
Brock,
At 25 filled:
If a1 = 3 or 6, I get e8 = 6 (1 step), but a1 could also be 4 in my setup. If a1 = 4, I needed 4 steps to show row 1 has only 3 numbers for 4 squares.

After eliminating a1 = 4, then e8 = 6 which if I were GB or Ohio Steve would be easy fill to 81 - however I More...
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kaz
In today's puzzle, at 25 filled, I look at the cells d7 = 258, e7 = 458, f7 = 42. For the purposes of the proof, I could care less exactly what each of those three cells contain, only that the union of their contents is 2548 - 4 possibilities in 3 cells. (n being 3). Clearly, then, amongst More...
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Ok - I mean amongst the many, many non-native weak links that the set implies...are the ones i used in the proof. Hopefully this clears things up.
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Basically, I argue that anything that forbids any two (or more)of the possiblities of 2,5,4,8 from the three cells, d7,f7,e7 is forbidden. Then I just pick which of those forbidden occurences forwards whatever proof I choose to use.
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forgot to restart the timer
but had a guess anyway
wish it would stop signing we out
havea great day/night one and all
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BTW - the penalty for such a step is 3 sets and depth 3 added to whatever other sets and depth are needed in the rest of the proof step.
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Congratulations to Fi on a beautiful photo - hope to get the opportunity to see it in real life one day soon
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Correction - not sure what I was thinking...If a1 = 3, f9 = 9 (not e8). I think its easiest to show that f9 = 6 is impossible, but it takes me quite a few steps, so maybe your method is easier, but you still have to eliminate a9 = 4.
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16:13
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38:20 Now that was tough!
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Thanks for the explanation but, my word, it's complicated, don't know if I'd ever be able to put it into practice!
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Fi, Nice pic hope there's no crocs
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We had an easy time with this one- no set up, just patience and logic, no possibilities and no guessing.
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Can anyone please tell me how I can populate all the blank squares with every number from 1-9 as possibilities without having to enter each of them one-by-one?
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11:11
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10:18, a good time for me. good maEveningn
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Hi Christina, it's good to read from you again. Any new painting?
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Mine was a bit of a mix between Valy's and Brock's I think. Eliminated the 4 in a9 easily but didn't write it out. I know I used the same x-wing as Valy in the process. Then if a9=3, i9=5 and g8=2,so i8=9. Also If a9=3,b79<>3,so b1=3 -> i1=9. Since i8 and i1 cant both be 9, a9 must be 6. Easy from there. Not game yet to try your terminology, though I can follow it now.
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1. Unique placemnts to 25
2. X-wing in 7's R19
3. Hidden triple 375 in b1,b7,b9 and b9,h9,i9
4. If a9 = 3 or 6, then e8 must = 6
5. easy fill to 81

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step 4 must be wrong
if a9=3, b7=5, e8=5
am I missing something?
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am I posting on today's (Still to be done) or yesterday's puzzle, that I've just completed?
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19:30 w/couple of guesses.
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July 2, 2007.
03/Jul/07 3:58 AM
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SE=7.3
05/Sep/10 10:17 AM
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