Sudoku Puzzles

Such beautifully exoctic things we see on this site! Thanks, Kate!

Very very nice picture Kate Nice week end to all of us

Hi everyone ~ Guess I am getting more adventurous! This is my first time to try a 'tough' puzzle - - thank goodness for being able to check our progress along the way, but it was easier than I had expected!

Nice picture, Kate. I reminds me of a bottle-brush tree that grew by the gate at our first house. The hummingbirds and butterflies just loved it! Thanks for sharing.

1) Start 22, Unique Possibilities to (UP) 27.
2) Locked 7s at f45 forbid d5=7, e45=7.
3) e2=9 == d3=9 -- d5=9 == d5=4 -- d7=4 == d7=8 -- e9=8 == e9=5 forbids e2=5. UP 35.
4) Locked 9s at c79 forbid c4=9.
5) Hidden pair 57 at h45 forbids h4=39, h5=239. UP 81.

16:29

It looks like a bottle brush to me.

A good one Kate!

Kate - callistemon? Lovely photo.

2:27:09 went away and left the timer running. I've been to town and back, made a strawberry pie, cooked the chicken for chicken salad, watched about 30 YouTube videos, planned what two of my kids will wear to a baby shower tomorrow, been on 5 different phone calls, read some of your postings, wrote More...

1. Start at 22 filled. Unique Possibilities(UP)to 27.
2a. hp59 at d3e2, d3<>1, e2<>26.
2b. locked 7's at f45, d5, e56<>7.
2c. hp27 at e18, e1<>6, e8<>58. UP28
3a. hp57 at h45, h4<>39, h5<>239.
3b. locked 9's at a56, c4<>9.
3c. (9)e4 More...

21:22

An alternative path:
After Dave's step 3b use:
(9=5)e2-(5=8)e9-(8=4)d7-(4=9)d5 => d3,e46<>9. UP81

Another path:

1)Start at 22,=>UP=27

2)fc:(6)f23=(6-7)f5=(7-1)f4=(1)d6-(1=7)d1-(7)d8=(7-2)e8=(2)e1
=>e1<>6,f23 <>2.UP=81

15.43 Once again Kate, you make me marvel at our native plants, something I would normally take for granted.

10:10, but should have been faster. We've got some of them in the front yard and your photo reminds me that they need a little TLC this weekend Kate.

Wow...never seen anything like it.... Beautiful and yes! exotic! Thanks Kate for widening my horizon...

sotir,
Your chain proves that (6)f23=(2)e1. This means that at least one of these two premises must be true, it does not guarantee they are both true. The first part of your conclusion is correct since either e1=2 or there is a 6 located in either f2 or f3 and thus there can in no case be a 6 More...

Hi Jeff,

What about: 2)....=(7-2)d8=(2)f7,=>f12<>2. UP=81

Sorry,

(7-2)d8 to read (7-2)e8

Thanks everyone. It could be a Callistemon or a Melaleuca, Ian, but I think it might be the Crimson bottlebrush - Callistemon citrinus (also called the lemon bottle brush, because of it's scent!) We have both up the river & I can't remember which this was. A lot of Melaleuca (paperbarks) are yellow, but there is a red one Melaleuca hypericifolia (which is up there, too).

Your new chain gives us (6)f23==(2)f7 and if f2 or f3 is 6 the chain is satisfied and then either f3 or f2 may be 2. The basic problem is that you have only 2 candidates to cover 3 cells. If you were making conclusion about the chain end that consists of only 1 cell you would be fine as long as both cells at the other end can see the one cell end.